Mathematics · Definite Integration

JEE Main 2024 — 4 April, Shift 1 — Question 9

Let f(x)={−2,−2≤x≤0x−2,0<x≤2f\left( \text{x} \right)=\left\{ \begin{matrix}-2, & -2\le \text{x}\le 0 \\\text{x}-2, & 0<\text{x}\le 2 \\\end{matrix} \right. and h(x)=f(∣x∣)+∣f(x)∣\text{h}\left( \text{x} \right)=\text{f}\left(\left| \text{x}\right| \right)+\left| \text{f}\left( \text{x} \right) \right|.Then ∫−22  ⁣ ⁣  ⁣ ⁣ h(x)dx\int _{-2}^{2}\text{ }\!\!~\!\!\text{ h}\left( \text{x} \right)\text{dx} is equal to :

  1. Option A:

    2

    Correct
  2. Option B:

    4

  3. Option C:

    1

  4. Option D:

    6

Answer: A

Step-by-step solution

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Definite Integration
Topic
Evaluation of Definite Integrals
Let f ( x )= \ begin matrix -2, & -2le x le 0 \\ x -2, & 0< x le 2… | JEE Main 2024 PYQ with Solution · DhiX AI