Mathematics · Sequence and Series

JEE Main 2024 — 31 January, Shift 2 — Question 9

Let 2nd ,8th 2^{\text {nd }}, 8^{\text {th }} and 44th 44^{\text {th }}, terms of a non-constant A.P. be respectively the 1st ,2nd 1^{\text {st }}, 2^{\text {nd }} and 3rd 3^{\text {rd }} terms of G.P. If the first term of A.P. is 1 then the sum of first 20 terms is equal to-

  1. Option A:

    980

  2. Option B:

    960

  3. Option C:

    990

  4. Option D:

    970

    Correct

Answer: D

Step-by-step solution

1+d,1+7 d,1+43 d1+\mathrm{d}, 1+7 \mathrm{~d}, 1+43 \mathrm{~d} are in GP

(1+7d)2=(1+d)(1+43 d)(1+7 d)^{2}=(1+d)(1+43 \mathrm{~d})

1+49 d2+14d=1+44d+43 d21+49 \mathrm{~d}^{2}+14 d=1+44 d+43 \mathrm{~d}^{2}

6d2−30d=06 d^{2}-30 d=0

d=5\mathrm{d}=5

S20=202[2×1+(20−1)×5]=10[2+95]=970\begin{aligned}\mathrm{S}_{20} & =\frac{20}{2}[2 \times 1+(20-1) \times 5] &=10[2+95] & =970\end{aligned}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Sequence and Series
Topic
Geometric Progression
Let 2 nd , 8 th and 44 th , terms of a non-constant A.P. be… | JEE Main 2024 PYQ with Solution · DhiX AI