Mathematics · Matrices

JEE Main 2026 — 23 January, Evening Shift — Question 24

Let A=[02−3−2013−10]\mathrm{A}=\left[\begin{array}{ccc}0 & 2 & -3 \\-2 & 0 & 1 \\3 & -1 & 0\end{array}\right] and B be a matrix such that B(I−A)=I+A\mathrm{B}(\mathrm{I}-\mathrm{A})=\mathrm{I}+\mathrm{A}. Then the sum of the diagonal elements of BTB\mathrm{B}^{\mathrm{T}} \mathrm{B} is equal to ____\_\_\_\_ .

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

AT=−AA^{T}=-A

B=(I+A)(I−A)−1\mathrm{B}=(\mathrm{I}+\mathrm{A})(\mathrm{I}-\mathrm{A})^{-1}

BT=((I−A)−1)T(I+A)TB^{T}=\left((I-A)^{-1}\right)^{T}(I+A)^{T}

BT=(I−AT)−1(I+AT)B^{T}=\left(I-A^{T}\right)^{-1}\left(I+A^{T}\right)

BT=(I+A)−1(I+A)\mathrm{B}^{\mathrm{T}}=(\mathrm{I}+\mathrm{A})^{-1}(\mathrm{I}+\mathrm{A})

BTB=(I+A)−1(I−A)(I+A)(I−A)−1\mathrm{B}^{\mathrm{T}} \mathrm{B}=(\mathrm{I}+\mathrm{A})^{-1}(\mathrm{I}-\mathrm{A})(\mathrm{I}+\mathrm{A})(\mathrm{I}-\mathrm{A})^{-1}

=(I+A)−1(I+A)(I−A)(I−A)−1=(\mathrm{I}+\mathrm{A})^{-1}(\mathrm{I}+\mathrm{A})(\mathrm{I}-\mathrm{A})(\mathrm{I}-\mathrm{A})^{-1} =I=\mathrm{I}

tr⁡(BTB)=3\operatorname{tr}\left(\mathrm{B}^{\mathrm{T}} \mathrm{B}\right)=3

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Matrices
Topic
Inverse of a Matrix
Let A = [begin array ccc 0 & 2 & -3 \\-2 & 0 & 1 \\3 & -1 & 0end… | JEE Main 2026 PYQ with Solution · DhiX AI