Mathematics · Vector Algebra

JEE Main 2025 — 2 April, Evening Shift — Question 36

Let a⃗=2i^−3j^+k^,b⃗=3i^+2j^+5k^\vec{a}=2 \hat{i}-3 \hat{j}+\hat{k}, \vec{b}=3 \hat{i}+2 \hat{j}+5 \hat{k} and a vector c⃗\vec{c} be such that (a⃗−c⃗)×b⃗=−18i^−3j^+12k^(\vec{a}-\vec{c}) \times \vec{b}=-18 \hat{i}-3 \hat{j}+12 \hat{k}

and a⃗⋅c⃗=3\vec{a} \cdot \vec{c}=3. If b⃗×c⃗=d⃗\vec{b} \times \vec{c}=\vec{d}, then ∣a⃗⋅d⃗∣|\vec{a} \cdot \vec{d}| is equal to :

  1. Option A:

    9

  2. Option B:

    12

  3. Option C:

    18

  4. Option D:

    15

    Correct

Answer: D

Step-by-step solution

(a⃗−c⃗)×b⃗=−18i^−3j^+12k^(\vec{a}-\vec{c}) \times \vec{b}=-18 \hat{i}-3 \hat{j}+12 \hat{k}

a⃗×b⃗−c⃗×b⃗=−18i^−3j^+12k^\vec{a} \times \vec{b}-\vec{c} \times \vec{b}=-18 \hat{i}-3 \hat{j}+12 \hat{k}

⇒a⃗×b⃗+d⃗=−18i^−3j^+12k^\Rightarrow \vec{a} \times \vec{b}+\vec{d}=-18 \hat{i}-3 \hat{j}+12 \hat{k}

Take dot with a⃗\vec{a}

a⃗⋅d⃗=−36+9+12=−15\vec{a} \cdot \vec{d}=-36+9+12=-15

∴∣a⃗⋅d⃗∣=15\therefore|\vec{a} \cdot \vec{d}|=15

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Vector Algebra
Topic
Applications of Vectors
Let vec a =2 hat i -3 hat j +hat k , vec b =3 hat i +2 hat j +5 hat k… | JEE Main 2025 PYQ with Solution · DhiX AI