Mathematics · Sets and Relations

JEE Main 2024 — 4 April, Shift 2 — Question 4

Let a relation R on N×N\mathbb{N} \times \mathbb{N} be defined as : (x1,y1)R(x2,y2)\left(x_{1}, y_{1}\right) R\left(x_{2}, y_{2}\right) if and only if x1≤x2x_{1} \leq x_{2} or y1≤y2y_{1} \leq y_{2} Consider the two statements :

(I) R is reflexive but not symmetric.

(II) R is transitive

Then which one of the following is true?

  1. Option A:

    Only (II) is correct.

  2. Option B:

    Only (I) is correct.

    Correct
  3. Option C:

    Both (I) and (II) are correct.

  4. Option D:

    Neither (I) nor (II) is correct.

Answer: B

Step-by-step solution

All ((x1y1),(x1,y1))\left(\left(\mathrm{x}_{1} \mathrm{y}_{1}\right),\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)\right) are in R where

x1,y1∈ N\mathrm{x}_{1}, \mathrm{y}_{1} \in \mathrm{~N} ∴R\therefore \mathrm{R} is reflexive

((1,1),(2,3))∈R((1,1),(2,3)) \in R

but ((2,3),(1,1))∉R((2,3),(1,1)) \notin R

∴R\therefore \mathrm{R} is not symmetric

((2,4),(3,3))∈R((2,4),(3,3)) \in \mathrm{R} and ((3,3),(1,3))∈R((3,3),(1,3)) \in \mathrm{R}

but ((2,4)((2,4), (1,3))∉R(1,3)) \notin \mathrm{R}

∴R\therefore \mathrm{R} is not transitive

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Sets and Relations
Topic
Types of Relations
Let a relation R on mathbb N × mathbb N be defined as : (x 1 , y 1 )… | JEE Main 2024 PYQ with Solution · DhiX AI