Mathematics · Circles

JEE Main 2025 — 29 January, Evening Shift — Question 55

Let a circle CC pass through the points (4,2)(4,2) and (0(0, 2 ), and its centre lie on 3x+2y+2=03 x+2 y+2=0.

Then the length of the chord, of the circle C , whose midpoint is (1,2)(1,2), is

  1. Option A:

    3\sqrt{3}

  2. Option B:

    232 \sqrt{3}

    Correct
  3. Option C:

    424 \sqrt{2}

  4. Option D:

    222 \sqrt{2}

Answer: B

Step-by-step solution

MAB=0⇒OM\mathrm{M}_{\mathrm{AB}}=0 \Rightarrow \mathrm{OM} is vertical

⇒α=2\Rightarrow \alpha=2

∴\therefore Centre (0)≡(2,−4)(0) \equiv(2,-4)

r=OA=(2−4)2+(2+4)2=40\mathrm{r}=\mathrm{OA}=\sqrt{(2-4)^{2}+(2+4)^{2}}=\sqrt{40}

mid point of chord is N≡(1,2)∴ON=37\mathrm{N} \equiv(1,2) \quad \therefore \mathrm{ON}=\sqrt{37}

∴\therefore length of chord =2r2−(ON)2=2 \sqrt{\mathrm{r}^{2}-(\mathrm{ON})^{2}}

=240−37=23=2 \sqrt{40-37}=2 \sqrt{3}
Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Circles
Topic
Chords connected with a Circle
Let a circle C pass through the points (4,2) and (0 , 2 ), and its… | JEE Main 2025 PYQ with Solution · DhiX AI