Chemistry · Solutions and Colligative Properties

JEE Main 2025 — 4 April, Morning Shift — Question 10

XYX Y is the membrane/partition between two chambers 1 and 2 containing sugar solutions of concentration C1\mathrm{C}_{1} and C2(C1>C2)molL−1\mathrm{C}_{2}\left(\mathrm{C}_{1}>\mathrm{C}_{2}\right) \mathrm{mol} \mathrm{L}^{-1}. For the reverse osmosis to take place identify the correct condition. (Here p1p_{1} and p2p_{2} are pressures applied on chamber 1 and 2)

A. Membrane/Partition: Cellophane, p1>π\mathrm{p}_{1}>\pi

B. Membrane/Partition : Porous, p2>π\mathrm{p}_{2}>\pi

C. Membrane/Partition : Parchment paper, p1>π\mathrm{p}_{1}>\pi

D. Memberane/Partition: Cellophane, p2>π\mathrm{p}_{2}>\pi

Choose the correct answer from the option given below.

Question figure
  1. Option A:

    A and D only

  2. Option B:

    A and C only

    Correct
  3. Option C:

    C only

  4. Option D:

    B and D only

Answer: B

Step-by-step solution

Membrane should be cellophane or parchment paper i.e., semipermeable membrane. And for reverse osmosis, the

pressure p1>\mathrm{p}_{1}> osmotic pressure ( π\pi ).

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Solutions and Colligative Properties
Topic
Liquid in Liquid Solutions (Raoult's Law)
X Y is the membrane/partition between two chambers 1 and 2 containing… | JEE Main 2025 PYQ with Solution · DhiX AI