Mathematics · Definite Integration

JEE Main 2024 — 6 April, Shift 1 — Question 3

∫0π/4cos⁡2xsin⁡2x(cos⁡3x+sin⁡3x)2dx\int_{0}^{\pi / 4} \frac{\cos ^{2} x \sin ^{2} x}{\left(\cos ^{3} x+\sin ^{3} x\right)^{2}} d x is equal to

  1. Option A:

    1/121 / 12

  2. Option B:

    1/91 / 9

  3. Option C:

    1/61 / 6

    Correct
  4. Option D:

    1/31 / 3

Answer: C

Step-by-step solution

Divide Nr & Dr by cosx ∫0π/4tan⁡2xsec⁡2xdx(1+tan⁡3x)2dx\int_{0}^{\pi / 4} \frac{\tan ^{2} x \sec ^{2} x d x}{\left(1+\tan ^{3} x\right)^{2}} d x

Let 1+tan⁡3x=t1+\tan ^{3} \mathrm{x}=\mathrm{t}

tan⁡2xsec⁡2xdx=dt3\tan ^{2} x \sec ^{2} x d x=\frac{d t}{3}

13∫12dtt2=16\frac{1}{3} \int_{1}^{2} \frac{d t}{t^{2}}=\frac{1}{6}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Definite Integration
Topic
Methods of solving definite integrals(kings rule,odd even)
int 0 π / 4 frac cos 2 x sin 2 x (cos 3 x+sin 3 x ) 2 d x is equal to | JEE Main 2024 PYQ with Solution · DhiX AI