Physics · Semiconductor and Electronic Devices

JEE Main 2025 — 7 April, Morning Shift — Question 58

In the following circuit, the reading of the ammeter will be (Take Zener breakdown voltage = 4 V )

Answer: A

Voltage across $400 \Omega$ resistor is 4 volts So $I=\frac{4}{400}=10 \mathrm{~mA}$

Answer key and solution verified before publishing.

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