Chemistry · Practical Inorganic chemistry (Qualitative Analysis)

JEE Main 2024 — 8 April, Shift 2 — Question 58

In qualitative test for identification of presence of phosphorous, the compound is heated with an oxidising agent. Which is further treated with nitric acid and ammonium molybdate respectively. The yellow coloured precipitate obtained is :

Option A:
$\mathrm{Na}_{3} \mathrm{PO}_{4} \cdot 12 \mathrm{MoO}_{3}$
Option B:
$\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4} \cdot 12\left(\mathrm{NH}_{4}\right)_{2} \mathrm{MoO}_{4}$
Option C:
$\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4} \cdot 12 \mathrm{MoO}_{3}$
Correct
Option D:
$\mathrm{MoPO}_{4} \cdot 21 \mathrm{NH}_{4} \mathrm{NO}_{3}$

Answer: C

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Exam: JEE Main 2024
Paper: 8 April, Shift 2
Subject: Chemistry
Chapter: Practical Inorganic chemistry (Qualitative Analysis)
Topic: Other Misc Reactions/ Tests