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Physics · Atomic Physics

JEE Main 2024 — 6 April, Shift 1 — Question 50

In photoelectric experiment energy of 2.48 eV irradiates a photo sensitive material. The stopping potential was measured to be 0.5 V . Work function of the photo sensitive material is :

  1. Option A:

    0.5 Ev

  2. Option B:

    1.68 eV

  3. Option C:

    2.48 eV

  4. Option D:

    1.98 eV

    Correct

Answer: D

Step-by-step solution

eVs=hv−ϕ\mathrm{eV}_{\mathrm{s}}=\mathrm{h} v-\phi

0.5 V=2.48−ϕ0.5 \mathrm{~V}=2.48-\phi

work function (ϕ)=2.48 V−0.5 V=1.98 V(\phi)=2.48 \mathrm{~V}-0.5 \mathrm{~V}=1.98 \mathrm{~V}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
6 April, Shift 1
Subject
Physics
Chapter
Atomic Physics
Topic
Photoelectric Effect

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