In an a.c. circuit, voltage and current are given by: V =100 sin (100 t ) V and I=100 sin (100 t+π/3 ) m A respectively. The average power dissipated in one cycle is :

Physics · Alternating Current

JEE Main 2024 — 29 January, Shift 2 — Question 33

In an a.c. circuit, voltage and current are given by: $\mathrm{V}=100 \sin (100 \mathrm{t}) \mathrm{V}$

and $I=100 \sin \left(100 t+\frac{\pi}{3}\right) m A$ respectively. The average power dissipated in one cycle is :

$\mathrm{P}_{\text {avg }}=\mathrm{V}_{\mathrm{rms}} \mathrm{I}_{\mathrm{rms}} \cos (\Delta \phi)$

$=\frac{100}{\sqrt{2}} \times \frac{100 \times 10^{-3}}{\sqrt{2}} \times \cos \left(\frac{\pi}{3}\right)$

$=\frac{10^{4}}{2} \times \frac{1}{2} \times 10^{-3}$

$=\frac{10}{4}=2.5 \mathrm{~W}$

Answer key and solution verified before publishing.

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.