Physics · Wave Optics

JEE Main 2025 — 4 April, Morning Shift — Question 51

In a Young's double slit experiment, the slits are separated by 0.2 mm . If the slits separation is increased to 0.4 mm , the percentage change of the fringe width is

Option A:
$25 \%$
Option B:
$50 \%$
Correct
Option C:
$0 \%$
Option D:
$100 \%$

Answer: B

Step-by-step solution

$\beta_{1}=\frac{\lambda D}{d}$

$\beta_{2}=\frac{\lambda D}{2 d}=\frac{\beta_{1}}{2}$

$\%$ change $=50 \%$

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 4 April, Morning Shift
Subject: Physics
Chapter: Wave Optics
Topic: Young's Double Slit Experiment and Its Modifications