Physics · Fluid Mechanics

JEE Main 2024 — 29 January, Shift 1 — Question 58

In a test experiment on a model aeroplane in wind tunnel, the flow speeds on the upper and lower surfaces of the wings are 70 ms−170 \mathrm{~ms}^{-1} and 65 ms−165 \mathrm{~ms}^{-1} respectively. If the wing area is 2 m22 \mathrm{~m}^{2} the lift of the wing is \qquad N . (Given density of air =1.2 kg m−3=1.2 \mathrm{~kg} \mathrm{~m}^{-3} )

Answer: 810

Numerical answer — enter this value.

Step-by-step solution

F=12ρ(v12−v22)A\mathrm{F}=\frac{1}{2} \rho\left(\mathrm{v}_{1}^{2}-\mathrm{v}_{2}^{2}\right) \mathrm{A} F=12×1.2×(702−652)×2\mathrm{F}=\frac{1}{2} \times 1.2 \times\left(70^{2}-65^{2}\right) \times 2

=810 N=810 \mathrm{~N}

Answer key and solution verified before publishing.

Practise Fluid Mechanics

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Main 2024
Subject
Physics
Chapter
Fluid Mechanics
Topic
Bernoulli's Equation and its Applications
In a test experiment on a model aeroplane in wind tunnel, the flow… | JEE Main 2024 PYQ with Solution · DhiX AI