Mathematics · Sets and Relations

JEE Main 2024 — 4 April, Shift 1 — Question 22

In a survey of 220 students of a higher secondary school, it was found that at least 125 and at most 130 students studied Mathematics; at least 85 and at most 95 studied Physics; at least 75 and at most 90 studied Chemistry; 30 studied both Physics and Chemistry; 50 studied both Chemistry and Mathematics; 40 studied both Mathematics and Physics and 10 studied none of these subjects. Let m and n respectively be the least and the most number of students who studied all the three subjects. Then m+n\mathrm{m}+\mathrm{n} is equal to \qquad

Answer: 45

Numerical answer — enter this value.

Step-by-step solution

125≤m+90−x≤130125 \leq \mathrm{m}+90-\mathrm{x} \leq 130

85≤P+70−x≤9585 \leq \mathrm{P}+70-\mathrm{x} \leq 95

75≤C+80−x≤9075 \leq \mathrm{C}+80-\mathrm{x} \leq 90

m+P+C+120−2x=210\mathrm{m}+\mathrm{P}+\mathrm{C}+120-2 \mathrm{x}=210 $

⇒15≤x≤45&30−x≥0\Rightarrow 15 \leq \mathrm{x} \leq 45 \& 30-\mathrm{x} \geq 0

⇒15≤x≤30\Rightarrow 15 \leq \mathrm{x} \leq 30

30+15=4530+15=45

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Sets and Relations
Topic
Sets
In a survey of 220 students of a higher secondary school, it was… | JEE Main 2024 PYQ with Solution · DhiX AI