Physics · Wave Optics

JEE Main 2024 — 5 April, Shift 2 — Question 52

In a single slit experiment, a parallel beam of green light of wavelength 550 nm passes through a slit of width 0.20 mm . The transmitted light is collected on a screen 100 cm away. The distance of first order minima from the central maximum will be $x \times 10^{-5} \mathrm{~m}$ . The value of $x$ is :

Answer: 275

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{y}=\frac{\lambda \mathrm{D}}{\mathrm{d}}=\frac{550 \times 10^{-9} \times 100 \times 10^{-2}}{0.2 \times 10^{-3}}=275$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 5 April, Shift 2
Subject: Physics
Chapter: Wave Optics
Topic: Diffraction of Light Waves