In a microscope the objective is having focal length f 0 =2 cm and eye-piece is having focal length f e =4 cm . The tube length is 32 cm . The magnification produced by this microscope for normal adjustment is \ \ \ \ .

Physics · Geometrical Optics

JEE Main 2026 — 21 January, Morning Shift — Question 47

In a microscope the objective is having focal length $f_{0}=2 \mathrm{~cm}$ and eye-piece is having focal length $f_{\mathrm{e}}=4 \mathrm{~cm}$ . The tube length is 32 cm . The magnification produced by this microscope for normal adjustment is $\_\_\_\_$ .

Answer: 100

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{m} \simeq \frac{\mathrm{lD}}{\mathrm{f}_{0} \mathrm{f}_{\mathrm{e}}}$

=\frac{32}{2} \times \frac{25}{4}

$\mathrm{m}=100$

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Exam: JEE Main 2026
Paper: 21 January, Morning Shift
Subject: Physics
Chapter: Geometrical Optics
Topic: Optical Instruments

A collimated beam of light of diameter 2 mm is propagating along x -axis. The beam is required to be expanded in a collimated beam of…

Answer: 100

Step-by-step solution

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