Mathematics · Trigonometry Ratios and Identities

JEE Main 2026 — 5 April, Evening Shift — Question 46

If S={θ∈[−π,π]:cos⁡θcos⁡5θ2=cos⁡7θcos⁡7θ2}\mathrm{S}=\left\{\theta \in[-\pi, \pi]: \cos \theta \cos \frac{5 \theta}{2}=\cos 7 \theta \cos \frac{7 \theta}{2}\right\}, then n(S)\mathrm{n}(\mathrm{S}) is equal to ____\_\_\_\_

Answer: 19

Numerical answer — enter this value.

Step-by-step solution

cos⁡θcos⁡5θ2=cos⁡7θcos⁡7θ2\cos \theta \cos \frac{5 \theta}{2}=\cos 7 \theta \cos \frac{7 \theta}{2} cos⁡7θ2+cos⁡3θ2=cos⁡21θ2+cos⁡7θ2\cos \frac{7 \theta}{2}+\cos \frac{3 \theta}{2}=\cos \frac{21 \theta}{2}+\cos \frac{7 \theta}{2} cos⁡21θ2−cos⁡3θ2=0\cos \frac{21 \theta}{2}-\cos \frac{3 \theta}{2}=0 −2sin⁡6θsin⁡9θ2=0-2 \sin 6 \theta \sin \frac{9 \theta}{2}=0 sin⁡6θ=0\sin 6 \theta=0 θ=0,±π6,±2π6,…±5π6,±π\theta=0, \pm \frac{\pi}{6}, \pm \frac{2 \pi}{6}, \ldots \pm \frac{5 \pi}{6}, \pm \pi \quad (13 solutions) sin⁡9θ2=0\sin \frac{9 \theta}{2}=0 θ=±2π9,±4π9,±8π9(6\theta= \pm \frac{2 \pi}{9}, \pm \frac{4 \pi}{9}, \pm \frac{8 \pi}{9} \quad(6 more solutions )) Total =19= 19 solutions

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Trigonometry Ratios and Identities
Topic
Periodicity of trigometric functions,Solutions of trigonometric equations
If S = \ θ in[-π, π]: cos θ cos 5 θ/2=cos 7 θ cos 7 θ/2 \ , then n (… | JEE Main 2026 PYQ with Solution · DhiX AI