Mathematics · Differential Equations

JEE Main 2024 — 1 February, Shift 2 — Question 29

If dxdy=1+x−y2y,x(1)=1\frac{d x}{d y}=\frac{1+x-y^{2}}{y}, x(1)=1, then 5x(2)5 x(2) is equal to :

Answer: 5

Numerical answer — enter this value.

Step-by-step solution

dxdy−xy=1−y2y\frac{d x}{d y}-\frac{x}{y}=\frac{1-y^{2}}{y}

Integrating factor =e∫−1ydy=1y=e^{\int-\frac{1}{y} d y}=\frac{1}{y}

x⋅1y=∫1−y2y2dyx \cdot \frac{1}{y}=\int \frac{1-y^{2}}{y^{2}} d y

xy=−1y−y+c\frac{x}{y}=\frac{-1}{y}-y+c

x=−1−y2+cyx=-1-y^{2}+c y

x(1)=1\mathrm{x}(1)=1

1=−1−1+c⇒c=31=-1-1+\mathrm{c} \Rightarrow \mathrm{c}=3

x=−1−y2+3yx=-1-y^{2}+3 y

5x(2)=5(−1−4+6)=55 x(2)=5(-1-4+6)=5

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Differential Equations
Topic
Methods of solving a First Order,First Degree Differential
If d x/d y=frac 1+x-y 2 y , x(1)=1 , then 5 x(2) is equal to : | JEE Main 2024 PYQ with Solution · DhiX AI