Chemistry · Redox Reactions

JEE Main 2024 — 30 January, Shift 1 — Question 76

2MnO4−+bI−+cH2O→xI2+yMnO2+zOH−2 \mathrm{MnO}_{4}^{-}+\mathrm{bI}^{-}+\mathrm{cH}_{2} \mathrm{O} \rightarrow \mathrm{xI}_{2}+\mathrm{yMnO}_{2}+\mathrm{zOH}^{-}

If the above equation is balanced with integer coefficients, the value of zz is \qquad

Answer: 8

Numerical answer — enter this value.

Step-by-step solution

Adding oxidation half and reduction half, net reaction is

2MnO4−+6I−+4H2O→3I2+2MnO2+8OH−2 \mathrm{MnO}_{4}^{-}+6 \mathrm{I}^{-}+4 \mathrm{H}_{2} \mathrm{O} \rightarrow 3 \mathrm{I}_{2}+2 \mathrm{MnO}_{2}+8 \mathrm{OH}^{-}

⇒z=8\Rightarrow \mathrm{z}=8

⇒\Rightarrow Ans 8

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
Redox Reactions
Topic
Types of Redox Reactions & Balancing of Redox Reactions
2 MnO 4 - + bI - + cH 2 O rightarrow xI 2 + yMnO 2 + zOH - If the… | JEE Main 2024 PYQ with Solution · DhiX AI