Physics · Nuclear Physics

JEE Main 2024 — 8 April, Shift 2 — Question 46

If $M_{o}$ is the mass of isotope ${ }_{5}^{12} B, M_{p}$ and $M_{n}$ are the masses of proton and neutron, then nuclear binding energy of isotope is :

Option A:
$\left(5 M_{p}+7 M_{n}-M_{o}\right) C^{2}$
Correct
Option B:
$\left(M_{o}-5 M_{p}\right) C^{2}$
Option C:
$\left(M_{o}-12 M_{n}\right) C^{2}$
Option D:
$\left(M_{o}-5 M_{p}-7 M_{n}\right) C^{2}$

Answer: A

Step-by-step solution

B.E. $=\Delta \mathrm{mC}^{2}$ $\left(5 \mathrm{M}_{\mathrm{p}}+7 \mathrm{M}_{\mathrm{n}}-\mathrm{M}_{\mathrm{o}}\right) \mathrm{C}^{2}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 8 April, Shift 2
Subject: Physics
Chapter: Nuclear Physics
Topic: Mass Defect, Binding Energy and Q-Value of Nuclear Reaction

In a hypothetical fission reaction 92 X^236 arrow 56 Y^141+ 36 Z^92+3 R The identity of emitted particles (R) is :

Answer: A

Step-by-step solution

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