Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 7 April, Morning Shift — Question 56

If $\in_{o}$ denotes the permittivity of free space and $\phi E$ is the flux of the electric field through the

area bounded by the closed surface, then dimensions of $\left(\epsilon_{0} \frac{d \phi_{E}}{d t}\right)$

are that of:

Answer: A

Dimension of $\epsilon_{0}\left(\frac{d \phi_{E}}{d t}\right)$ will be Same as electric

current So $\left[\epsilon_{0} \frac{d \phi_{E}}{d t}\right]=A$

Answer key and solution verified before publishing.

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