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Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 22 January, Morning Shift — Question 56

If B is magnetic field and μ0\mu_{0} is permeability of free space, then the dimensions of (B/μ0)\left(\mathrm{B} / \mu_{0}\right) is

  1. Option A:

    MT−2 A−1\mathrm{MT}^{-2} \mathrm{~A}^{-1}

  2. Option B:

    L−1AL^{-1} A

    Correct
  3. Option C:

    LT−2 A−1\mathrm{LT}^{-2} \mathrm{~A}^{-1}

  4. Option D:

    ML2T−2A−1M L^{2} T^{-2} A^{-1}

Answer: B

Step-by-step solution

B=μ0ni\quad \mathrm{B}=\mu_{0} \mathrm{ni} [Bμ0]=[ni]=L−1A1\left[\frac{B}{\mu_{0}}\right]=[n i]=L^{-1} A^{1}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
22 January, Morning Shift
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Units and Dimensions Analysis
If B is magnetic field and μ 0 is permeability of free space, then… | JEE Main 2025 PYQ with Solution · DhiX AI