Mathematics · Vector Algebra

JEE Main 2024 — 5 April, Shift 1 — Question 18

If A(1,−1,2),B(5,7,−6),C(3,4,−10)\mathrm{A}(1,-1,2), \mathrm{B}(5,7,-6), \mathrm{C}(3,4,-10) and D(−1,−4,−2)\mathrm{D}(-1,-4,-2) are the vertices of a quadrilateral ABCD ,

then its area is :

  1. Option A:

    122912 \sqrt{29}

    Correct
  2. Option B:

    242924 \sqrt{29}

  3. Option C:

    24724 \sqrt{7}

  4. Option D:

    48748 \sqrt{7}

Answer: A

Step-by-step solution

A(1,−1,2)\mathrm{A}(1,-1,2)

B(5,7,−6)\mathrm{B}(5,7,-6)

C(3,4,−10)\mathrm{C}(3,4,-10)

D(−1,−4,−2)\mathrm{D}(-1,-4,-2)

Area =12∣AC→×BD→∣=12∣(2i^+5j^−12k^)×(6i^+11j^−4k^)∣=\frac{1}{2}|\overrightarrow{\mathrm{AC}} \times \overrightarrow{\mathrm{BD}}|=\frac{1}{2}|(2 \hat{\mathrm{i}}+5 \hat{\mathrm{j}}-12 \hat{\mathrm{k}}) \times(6 \hat{\mathrm{i}}+11 \hat{\mathrm{j}}-4 \hat{\mathrm{k}})|

=12∣112i^−64j^−8k^∣=\frac{1}{2}|112 \hat{\mathrm{i}}-64 \hat{\mathrm{j}}-8 \hat{\mathrm{k}}|

=4∣14i^−8j^−k^∣=4|14 \hat{\mathrm{i}}-8 \hat{\mathrm{j}}-\hat{\mathrm{k}}|

=4196+64+1=4 \sqrt{196+64+1}

=4261=4 \sqrt{261}

=1229=12 \sqrt{29}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Vector Algebra
Topic
Vector or Cross Product of Two Vectors
If A (1,-1,2), B (5,7,-6), C (3,4,-10) and D (-1,-4,-2) are the… | JEE Main 2024 PYQ with Solution · DhiX AI