If an iron (III) complex with the formula [ Fe ( NH 3 ) x ( CN ) y ] - has no electron in its e g orbital, then the value of x+y is

Chemistry · Coordination Compounds

JEE Main 2024 — 4 April, Shift 2 — Question 67

If an iron (III) complex with the formula $\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{\mathrm{x}}(\mathrm{CN})_{\mathrm{y}}\right]^{-}$ has no electron in its $\mathrm{e}_{\mathrm{g}}$ orbital, then the value of $x+y$ is

Option A:
5
Option B:
6
Correct
Option C:
3
Option D:
4

Answer: B

Step-by-step solution

Complex is $\left[\mathrm{Fe}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{CN})_{4}\right]^{\Theta}$

$\mathrm{x}=2$

$y=4$

so $\mathrm{x}+\mathrm{y}=6$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 4 April, Shift 2
Subject: Chemistry
Chapter: Coordination Compounds
Topic: Theories of Bonding in Coordination Compounds

The number of unpaired d-electrons in [ Co ( H 2 O ) 6 ]^3+ is

Answer: B

Step-by-step solution

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