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Physics · Semiconductor and Electronic Devices

JEE Main 2024 — 4 April, Shift 2 — Question 35

Identify the logic gate given in the circuit :

Question figure
  1. Option A:

    NAND - gate

  2. Option B:

    OR - gate

    Correct
  3. Option C:

    AND gate

  4. Option D:

    NOR gate

Answer: B

Step-by-step solution

Y=A‾‾.Bˉ‾Y=\overline{\overline{\mathrm{A}}} . \overline{\bar{B}} By De-Morgan Law

Y=A+B‾‾Y=\overline{\overline{\mathrm{A}+\mathrm{B}}} Y=A+BY=A+B Hence OR gate

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
4 April, Shift 2
Subject
Physics
Chapter
Semiconductor and Electronic Devices
Topic
Boolean Algebra, Truth Tables and Logic Gates

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