Chemistry · Coordination Compounds

JEE Main 2026 — 5 April, Evening Shift — Question 58

Identify the correct statements from the following: (A) [Fe(C2O4)3]3−\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-} is the most stable complex among [Fe(OH)6]3−,[Fe(C2O4)3]3−\left[\mathrm{Fe}(\mathrm{OH})_{6}\right]^{3-},\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-} and [Fe(SCN)6]3−\left[\mathrm{Fe}(\mathrm{SCN})_{6}\right]^{3-} (B) The stability of [Cu(NH3)4]2+\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+} is greater than that of [Cu(en)2]2+\left[\mathrm{Cu}(\mathrm{en})_{2}\right]^{2+} (C) The hybridization of Fe in K4[Fe(CN)6]\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] is d2sp3\mathrm{d}^{2} \mathrm{sp}^{3} (D) [Fe(NO2)3Cl3]3−\left[\mathrm{Fe}\left(\mathrm{NO}_{2}\right)_{3} \mathrm{Cl}_{3}\right]^{3-} exhibits linkage isomerism (E) NO2−\mathrm{NO}_{2}^{-}and SCN−\mathrm{SCN}^{-}ligands are NOT ambidentate ligands Choose the correct answer from the options given below :

  1. Option A:

    A, B, C, D and E

  2. Option B:

    B, C and D only

  3. Option C:

    A, C and D only

    Correct
  4. Option D:

    A, C and E only

Answer: C

Step-by-step solution

[Fe(C2O4)3]3−\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]^{3-} has oxalate ion as ligand which leads to chelation thus maximum stability among given complexes. (B) Stability : [Cu(NH3)4]2+<[Cu(en)2]2+\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}<\left[\mathrm{Cu}(\mathrm{en})_{2}\right]^{2+}; due to higher CFSE and chelation. (C) K4[Fe(CN)6]\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right] ⇒Fe2+=[Ar]3 d6\Rightarrow \mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^{6} In presence of SFL the electronic configuration of Fe+2[t2 g6,eg0]\mathrm{Fe}^{+2}\left[\mathrm{t}_{2 \mathrm{~g}}^{6}, \mathrm{e}_{\mathrm{g}}^{0}\right], thus d2sp3\mathrm{d}^{2} \mathrm{sp}^{3} hybridized. (D) [Fe(NO2)3Cl3]3−\left[\mathrm{Fe}\left(\mathrm{NO}_{2}\right)_{3} \mathrm{Cl}_{3}\right]^{3-} has NO2−\mathrm{NO}_{2}^{-}as ambidentate ligand thus can show linakge isomerism. (E) NO2−\mathrm{NO}_{2}^{-}and SCN−\mathrm{SCN}^{-}both are ambidentate ligands.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Coordination Compounds
Topic
Fundamentals of Co-ordination Compounds
Identify the correct statements from the following: (A) [ Fe ( C 2 O… | JEE Main 2026 PYQ with Solution · DhiX AI