Chemistry · Alkyl and Aryl Halides

JEE Main 2024 — 4 April, Shift 1 — Question 72

Identify the correct set of reagents or reaction conditions ' X ' and ' Y ' in the following set of transformation.

Option A:
$\mathrm{X}=$ conc.alc. $\mathrm{NaOH}, 80^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{Br}_{2} / \mathrm{CHCl}_{3}$
Option B:
$\mathrm{X}=$ dil.aq. $\mathrm{NaOH}, 20^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{HBr} /$ acetic acid
Option C:
$\mathrm{X}=$ conc.alc. $\mathrm{NaOH}, 80^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{HBr}$ /acetic acid
Correct
Option D:
$\mathrm{X}=$ dil.aq. $\mathrm{NaOH}, 20^{\circ} \mathrm{C}, \mathrm{Y}=\mathrm{Br}_{2} / \mathrm{CHCl}_{3}$

Answer: C

$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{Br} \xrightarrow[80^{\circ} \mathrm{C}]{\mathrm{X}=\text { conc.alc. } \mathrm{NaOH}}$

Answer key and solution verified before publishing.

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