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Physics · Thermodynamics

JEE Main 2025 — 2 April, Evening Shift — Question 62

Identify the characteristics of an adiabatic process in a monoatomic gas. (A) Internal energy is constant. (B) Work done in the process is equal to the change in internal energy. (C) The product of temperature and volume is a constant. (D) The product of pressure and volume is a constant. (E) The work done to change the temperature from T1T_{1} to T2T_{2} is proportional to (T2−T1)\left(T_{2}-T_{1}\right). Choose the correct answer from the options given below:

  1. Option A:

    (A), (C), (E) only

  2. Option B:

    (B), (E) only

    Correct
  3. Option C:

    (A), (C), (D) only

  4. Option D:

    (B), (D) only

Answer: B

Step-by-step solution

For adiabatic process

Q=0Q=0

∴ΔU=−W\therefore \quad \Delta U=-W

B, E are correct

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
2 April, Evening Shift
Subject
Physics
Chapter
Thermodynamics
Topic
Different Thermodynamic Processes

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