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Chemistry · Coordination Compounds

JEE Main 2024 — 27 January, Shift 2 — Question 69

Identify from the following species in which d2sp3\mathrm{d}^{2} \mathrm{sp}^{3} hybridization is shown by central atom:

  1. Option A:

    [Co(NH3)6]3+\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}

    Correct
  2. Option B:

    BrF5\mathrm{BrF}_{5}

  3. Option C:

    [Pt(Cl)4]2−\left[\mathrm{Pt}(\mathrm{Cl})_{4}\right]^{2-}

  4. Option D:

    SF6\mathrm{SF}_{6}

Answer: A

Step-by-step solution

To identify species showing d2sp3 hybridization, we look for:\textbf{To identify species showing } d^2sp^3 \textbf{ hybridization, we look for:} Geometry: Octahedral (6 bonding pairs), involving inner (n-1)d orbitals\text{Geometry: Octahedral (6 bonding pairs), involving inner (n-1)d orbitals} (a) [Co(NH3)6]3+\textbf{(a) } [\mathrm{Co}(\mathrm{NH}_3)_6]^{3+} Co3+⇒Atomic number 27, configuration: [Ar] 3d6\text{Co}^{3+} \Rightarrow \text{Atomic number 27, configuration: } [\mathrm{Ar}]\,3d^6 NH3 is a strong field ligand⇒pairing occurs\text{NH}_3 \text{ is a strong field ligand} \Rightarrow \text{pairing occurs} ⇒Uses inner d-orbitals (3d)⇒d2sp3 hybridization\Rightarrow \text{Uses inner d-orbitals (3d)} \Rightarrow d^2sp^3 \text{ hybridization} Geometry: Octahedral⇒Correct\text{Geometry: Octahedral} \Rightarrow \boxed{\text{Correct}} (b) BrF5\textbf{(b) } \mathrm{BrF}_5 Br: Atomic number 35⇒7 valence electrons\text{Br: Atomic number 35} \Rightarrow \text{7 valence electrons} 5 bonds + 1 lone pair⇒6 electron regions⇒octahedral electron geometry\text{5 bonds + 1 lone pair} \Rightarrow \text{6 electron regions} \Rightarrow \text{octahedral electron geometry} But uses outer d-orbitals (4d)⇒Hybridization is sp3d2\text{But uses outer d-orbitals (4d)} \Rightarrow \text{Hybridization is } sp^3d^2 Not d2sp3⇒Incorrect\boxed{\text{Not } d^2sp^3} \Rightarrow \boxed{\text{Incorrect}} (c) [Pt(Cl)4]2−\textbf{(c) } [\mathrm{Pt}(\mathrm{Cl})_4]^{2-} Pt2+⇒5d8⇒square planar geometry\text{Pt}^{2+} \Rightarrow 5d^8 \Rightarrow \text{square planar geometry} Hybridization: dsp2⇒Incorrect\text{Hybridization: } dsp^2 \Rightarrow \boxed{\text{Incorrect}} (d) SF6\textbf{(d) } \mathrm{SF}_6 S: Atomic number 16, 6 bonding pairs with no lone pairs\text{S: Atomic number 16, 6 bonding pairs with no lone pairs} Geometry: Octahedral, Hybridization: sp3d2 (outer d-orbitals used)\text{Geometry: Octahedral, Hybridization: } sp^3d^2 \text{ (outer d-orbitals used)} Not d2sp3⇒Incorrect\boxed{\text{Not } d^2sp^3} \Rightarrow \boxed{\text{Incorrect}} Final Answer: (a) [Co(NH3)6]3+\textbf{Final Answer: } \boxed{(a)\ [\mathrm{Co}(\mathrm{NH}_3)_6]^{3+}}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
27 January, Shift 2
Subject
Chemistry
Chapter
Coordination Compounds
Topic
Properties and importance of Coordination Complexes

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