Physics · Current Electricity

JEE Main 2024 — 1 February, Shift 1 — Question 32

he reading in the ideal voltmeter (V)(\mathrm{V}) shown in the given circuit diagram is :

Question figure
  1. Option A:

    5 V

  2. Option B:

    10 V

  3. Option C:

    0 V

    Correct
  4. Option D:

    3 V

Answer: C

Step-by-step solution

i=Eeqreq=8×58×0.2i=\frac{{{E}_{eq}}}{{{r}_{eq}}}=\frac{8\times 5}{8\times 0.2}

\begin{array}{*{35}{r}}{} & \text{I}=25\text{ }\!\!~\!\!\text{ A} \\{} & \text{ }\!\!~\!\!\text{ V}=\text{E}-\text{ir} \\{} & ~=5-0.2\times 25 \\{} & ~=0 \\\end{array}

Answer key and solution verified before publishing.

Practise Current Electricity

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Main 2024
Subject
Physics
Chapter
Current Electricity
Topic
Circuit Analysis, Kirchhoff's Law and Nodal Analysis
he reading in the ideal voltmeter ( V ) shown in the given circuit… | JEE Main 2024 PYQ with Solution · DhiX AI