Chemistry · Structure of Atom
JEE Main 2026 — 21 January, Morning Shift — Question 62
Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.
Statement I: When an electric discharge is passed through gaseous hydrogen, the hydrogen molecules dissociate and the energetically excited hydrogen atoms produce electromagnetic radiation of discrete frequencies.
Statement II: The frequency of second line of Balmer series obtained from is equal to that of first line of Lyman series obtained from hydrogen atom.
In the light of the above statements, choose the correct answer from the options given below:
- Option A:Correct
Both Statement I and Statement II are true
- Option B:
Both Statement I and Statement II are false
- Option C:
Statement I is false but Statement II is true
- Option D:
Statement I is true but Statement II is false
Answer: A
Step-by-step solution
Statement I: Electric discharge dissociates into atoms. Excited atoms emit radiation during electronic transitions, producing discrete spectral lines. Hence, Statement I is true.
Statement II: Second Balmer line of :
\left(\frac{1}{2^2} - \frac{1}{4^2}\right)$$ $$\bar{\nu}_1 = 4R \left(\frac{1}{4} - \frac{1}{16}\right)$$\bar{\nu}_1 = \frac{3R}{4}
First Lyman line of hydrogen is $2 \to 1$ $$\bar{\nu}_2 = R \left(1 - \frac{1}{4}\right) = \frac{3R}{4}$$ Thus $\bar{\nu}_1 = \bar{\nu}_2$. Frequencies are equal. Hence, Statement II is true.Answer key and solution verified before publishing.
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- Exam
- JEE Main 2026
- Subject
- Chemistry
- Chapter
- Structure of Atom
- Topic
- Analysis of Spectra of H-like species