Chemistry · Alcohols, Ethers and Phenols

JEE Main 2024 — 6 April, Shift 1 — Question 62

Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.

Statement I : Picric acid is 2, 4, 6-trinitrotoluene.

Statement II : Phenol-2, 4-disulphuric acid is treated with conc. $\mathrm{HNO}_{3}$ to get picric acid.

In the light of the above statement, choose the most appropriate answer from the options given below :

Option A:
Statement I is incorrect but Statement II is correct
Correct
Option B:
Both Statement I and Statement II are incorrect.
Option C:
Statement I is correct but Statement II is incorrect.
Option D:
Both Statement I and Statement II are correct.

Answer: A

Step-by-step solution

Statement I is Incorrect: Picric acid is 2,4,6-trinitrophenol, not 2,4,6-trinitrotoluene. (2,4,6-trinitrotoluene is TNT, which is a different compound.)

Picric acid ( 2,4,6 - trinitrophenol)

Statement II is Correct: Picric acid is prepared by treating phenol-2,4-disulphonic acid with concentrated nitric acid. In this reaction, the $-\mathrm{SO_3H}$ groups are replaced by $-\mathrm{NO_2}$ groups to form picric acid.

\text{Phenol-2,4-disulphonic \;acid} \xrightarrow{\text{conc. } \mathrm{HNO_3}} \text{Picric \;acid}

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 6 April, Shift 1
Subject: Chemistry
Chapter: Alcohols, Ethers and Phenols
Topic: Phenols