Chemistry · Periodicity of Elements and Periodic Properties
JEE Main 2024 — 5 April, Shift 2 — Question 70
Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.
Statement I : The metallic radius of Na is and the ionic radius of Na is less than .
Statement II : Ions are always smaller in size than the corresponding elements.
In the light of the above statements, choose the correct answer from the options given below :
- Option A:Correct
Statement I is correct but Statement II is incorrect
- Option B:
Both Statement I and Statement II are correct
- Option C:
Both Statement I and Statement II are incorrect
- Option D:
Statement I is incorrect but Statement II is correct
Answer: A
Step-by-step solution
Statement I is Correct: The metallic radius of sodium is . On formation of , sodium loses one electron, which increases the effective nuclear charge per electron and causes contraction of size; hence, the ionic radius of is smaller than .
Statement II is Incorrect: Ions are not always smaller than their parent atoms; cations are smaller due to loss of electron(s), whereas anions are larger because of gain of electron(s) and increased electron–electron repulsion.
Thus, statement I is correct but statement II is incorrect.
Answer key and solution verified before publishing.
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- Exam
- JEE Main 2024
- Paper
- 5 April, Shift 2
- Subject
- Chemistry
- Chapter
- Periodicity of Elements and Periodic Properties
- Topic
- Periodicity in Physical Properties (shielding and sizes)