Chemistry · Periodicity of Elements and Periodic Properties

JEE Main 2024 — 5 April, Shift 2 — Question 70

Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.

Statement I : The metallic radius of Na is 1.86 A˚1.86\,\mathrm{\AA} and the ionic radius of Na+^+ is less than 1.86 A˚1.86\,\mathrm{\AA}.

Statement II : Ions are always smaller in size than the corresponding elements.

In the light of the above statements, choose the correct answer from the options given below :

  1. Option A:

    Statement I is correct but Statement II is incorrect

    Correct
  2. Option B:

    Both Statement I and Statement II are correct

  3. Option C:

    Both Statement I and Statement II are incorrect

  4. Option D:

    Statement I is incorrect but Statement II is correct

Answer: A

Step-by-step solution

Statement I is Correct: The metallic radius of sodium is 1.86 A˚1.86\,\text{\AA}. On formation of (Na+)(\mathrm{Na^+}), sodium loses one electron, which increases the effective nuclear charge per electron and causes contraction of size; hence, the ionic radius of Na+\mathrm{Na^+} is smaller than 1.86 A˚1.86\,\text{\AA}.

Statement II is Incorrect: Ions are not always smaller than their parent atoms; cations are smaller due to loss of electron(s), whereas anions are larger because of gain of electron(s) and increased electron–electron repulsion.

Thus, statement I is correct but statement II is incorrect.

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
Periodicity of Elements and Periodic Properties
Topic
Periodicity in Physical Properties (shielding and sizes)
Given below are two statements, one is labelled as Statement I and… | JEE Main 2024 PYQ with Solution · DhiX AI