Chemistry · Nitrogen Containing Organic Compounds
JEE Main 2024 — 1 February, Shift 1 — Question 75
Given below are two statements, one is labelled as Statement I and the other is labelled as Statement II.
Statement (I) : The group in Aniline is ortho and para directing and a powerful activating group.
Statement (II) : Aniline does not undergo Friedel-Craft's reaction (alkylation and acylation).
In the light of the above statements, choose the most appropriate answer from the options given below :
- Option A:Correct
Both Statement I and Statement II are correct
- Option B:
Both Statement I and Statement II are incorrect
- Option C:
Statement I is incorrect but Statement II is correct
- Option D:
Statement I is correct but Statement II is incorrect
Answer: A
Step-by-step solution
Statement I is Correct: The group in aniline is a strong electron-donating group due to the lone pair on nitrogen. It activates the benzene ring and directs incoming electrophiles to the ortho and para positions.
Statement II is Correct: Aniline does not undergo Friedel-Crafts alkylation or acylation because the lone pair on nitrogen coordinates with the Lewis acid catalyst (), forming a salt that deactivates the benzene ring.
Thus, both Statement I and Statement II are correct (Option A).
Answer key and solution verified before publishing.
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- Exam
- JEE Main 2024
- Paper
- 1 February, Shift 1
- Subject
- Chemistry
- Chapter
- Nitrogen Containing Organic Compounds
- Topic
- Aniline