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Physics · Thermodynamics

JEE Main 2026 — 2 April, Evening Shift — Question 51

Gas 'A' undergoes change from state ' X ' to state ' Y '. In this process, the heat absorbed and work done by the gas is 10 J and 18 J respectively. Now gas is brought back to state ' X ' by another process during which 6 J of heat is evolved. In the reverse process of ' Y ' to ‘ X ’.

  1. Option A:

    18 J of the work is done by the gas ' A '.

  2. Option B:

    2 J of the work is done by the gas ' A '.

  3. Option C:

    12 J of the work is done on the gas 'A' by the surrounding.

  4. Option D:

    14 J of the work is done on the gas ' A ' by the surrounding

    Correct

Answer: D

Step-by-step solution

For process

X→Y\mathrm{X} \rightarrow \mathrm{Y} w=−18 J\mathrm{w}=-18 \mathrm{~J} q=+10 J\mathrm{q}=+10 \mathrm{~J} ΔU=q+w\Delta \mathrm{U}=\mathrm{q}+\mathrm{w} ΔUX→Y=10+(−18)=−8 J\Delta \mathrm{U}_{\mathrm{X} \rightarrow \mathrm{Y}}=10+(-18)=-8 \mathrm{~J}

For reverse process :

ΔUY→X=8 J\Delta \mathrm{U}_{\mathrm{Y} \rightarrow \mathrm{X}}=8 \mathrm{~J} q=−6 J\mathrm{q}=-6 \mathrm{~J} ΔU=q+w\Delta \mathrm{U}=\mathrm{q}+\mathrm{w} 8=−6+w8=-6+w w=14 J\mathrm{w}=14 \mathrm{~J}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
2 April, Evening Shift
Subject
Physics
Chapter
Thermodynamics
Topic
First Law of Thermodynamics

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