Mathematics · Definite Integration

JEE Main 2026 — 4 April, Evening Shift — Question 45

From a month of 31 days, 3 different dates are selected at random. If the probability that these dates are in an increasing A.P. is equal to ab\dfrac{a}{b}, where a, b∈Na,\ b \in \mathbb{N} and gcd⁡(a,b)=1\gcd(a,b) = 1, then a+ba + b is equal to ‾.\underline{\hspace{1.5cm}}.

Answer: 944

Numerical answer — enter this value.

Step-by-step solution

Total numbers of ways of selecting 3 numbers =31C3=31×30×293×2×1=4495={ }^{31} \mathrm{C}_{3}=\frac{31 \times 30 \times 29}{3 \times 2 \times 1}=4495 a,b,c\mathrm{a}, \mathrm{b}, \mathrm{c} are in A.P. ⇒ either a&c\mathrm{a} \& \mathrm{c} both odd numbers or both even numbers =16C2+15C2={ }^{16} \mathrm{C}_{2}+{ }^{15} \mathrm{C}_{2} =120+105=120+105 =225=225 Probability =2254495=45899=\frac{225}{4495}=\frac{45}{899} =ab⇒a+b=944=\frac{\mathrm{a}}{\mathrm{b}} \Rightarrow \mathrm{a}+\mathrm{b}=944

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Definite Integration
Topic
Introduction to Definite Integration
From a month of 31 days, 3 different dates are selected at random. If… | JEE Main 2026 PYQ with Solution · DhiX AI