Chemistry · Nitrogen Containing Organic Compounds

JEE Main 2024 — 4 April, Shift 2 — Question 78

From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be $\qquad$ $\times 10^{-1} \mathrm{~g}$

Answer: 95

Numerical answer — enter this value.

93 g aniline form 135 gm acetanlide so

$\quad 6.55 \mathrm{~g}$ anilne form $\frac{135}{93} \times 6.55=9.5$

$95 \times 10^{-1}$

Answer key and solution verified before publishing.

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