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Physics · Work, Power & Energy

JEE Main 2024 — 6 April, Shift 1 — Question 46

Four particles A, B, C, D of mass m2,m,2m,4m\frac{m}{2}, m, 2 m, 4 m, have same momentum, respectively. The particle with maximum kinetic energy is :

  1. Option A:

    D

  2. Option B:

    C

  3. Option C:

    A

    Correct
  4. Option D:

    B

Answer: C

Step-by-step solution

KE=p22 m\mathrm{KE}=\frac{\mathrm{p}^{2}}{2 \mathrm{~m}}

Same momentum, so less mass means more KE.

So m2\frac{\mathrm{m}}{2} will have max. KE.

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
6 April, Shift 1
Subject
Physics
Chapter
Work, Power & Energy
Topic
Kinetic Energy and Work-Energy Theorem

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