K a for CH 3 COOH is 1.8 × 10 -5 and K b for NH 4 OH is 1.8 × 10 -5 . The pH of ammonium acetate solution will be

Chemistry · Ionic Equilibrium

JEE Main 2024 — 1 February, Shift 1 — Question 82

$\mathrm{K}_{\mathrm{a}}$ for $\mathrm{CH}_{3} \mathrm{COOH}$ is $1.8 \times 10^{-5}$ and $\mathrm{K}_{\mathrm{b}}$ for $\mathrm{NH}_{4} \mathrm{OH}$ is $1.8 \times 10^{-5}$ . The pH of ammonium acetate solution will be

Answer: 7

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{pH}=\frac{\mathrm{pK}_{\mathrm{w}}+\mathrm{pK}_{\mathrm{a}}-\mathrm{pK}_{\mathrm{b}}}{2}$

$\mathrm{pK}_{\mathrm{a}}=\mathrm{pK}_{\mathrm{b}}$

$\Rightarrow \mathrm{pH}=\frac{\mathrm{pK}_{\mathrm{w}}}{2}=7$

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Exam: JEE Main 2024
Paper: 1 February, Shift 1
Subject: Chemistry
Chapter: Ionic Equilibrium
Topic: pH of solution containing implicit reaction