Energy released when two deuterons ( 1 H 2 ) fuse to form a helium nucleus ( 2 He 4 ) is (Given: Binding energy per nucleon of 1 H 2 =1.1 MeV and binding energy per nucleon of 2 He 4 =7.0 MeV )

Physics · Nuclear Physics

JEE Main 2025 — 2 April, Evening Shift — Question 48

Energy released when two deuterons $\left({ }_{1} \mathrm{H}^{2}\right)$ fuse to form a helium nucleus

$\left({ }_{2} \mathrm{He}^{4}\right)$ is (Given: Binding energy per nucleon

of ${ }_{1} \mathrm{H}^{2}=1.1 \mathrm{MeV}$ and binding energy per nucleon

of ${ }_{2} \mathrm{He}^{4}=7.0 \mathrm{MeV}$ )

$2{ }_{1} \mathrm{H}^{2} \rightarrow{ }_{2} \mathrm{He}^{4}$

\begin{aligned} Q & =(4 \times 7-4 \times 1.1) \mathrm{MeV} & =23.6 \mathrm{MeV} \end{aligned}

Answer key and solution verified before publishing.

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