Displacement of a wave is expressed as x(t)=5 cos (628 t+π/2 ) m . The wavelength of the wave when its velocity is 300 m / s is : ( π=3.14 )

Physics · Transverse waves

JEE Main 2025 — 4 April, Evening Shift — Question 44

Displacement of a wave is expressed as $x(t)=5 \cos \left(628 t+\frac{\pi}{2}\right) \mathrm{m}$ .

The wavelength of the wave when its velocity is $300 \mathrm{~m} / \mathrm{s}$ is : ( $\pi=3.14$ )

$x=5 \cos \left(628 t+\frac{\pi}{2}\right)$ $2 \pi f=628$ $6.28 f=628$ $f=100 \mathrm{H}_{2}$ $\lambda=\frac{v}{f}=\frac{300}{100}=3 \mathrm{~m}$

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