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Physics · Units, Dimensions & Error Analysis

JEE Main 2026 — 2 April, Evening Shift — Question 1

Dimensions of universal gravitational constant (G) in terms of Planck's constant (h)(h) , distance 00 , mass (M)(M) and time (T)(T) are

  1. Option A:

    [hTLM−2]\left[\mathrm{hTLM}^{-2}\right]

  2. Option B:

    [hT−1LM−2]\left[\mathrm{hT}^{-1}\mathrm{LM}^{-2}\right]

    Correct
  3. Option C:

    [hTL−2M−2]\left[\mathrm{hTL}^{-2}\mathrm{M}^{-2}\right]

  4. Option D:

    [h−1T−1LM−2]\left[\mathrm{h}^{-1}\mathrm{T}^{-1}\mathrm{LM}^{-2}\right]

Answer: B

Step-by-step solution

Energy=hcλ=GM1M2r\mathrm{Energy} = \frac{\mathrm{hc}}{\lambda} = \frac{\mathrm{GM}_{1}\mathrm{M}_{2}}{\mathrm{r}} [ML−2T−2]=[h][T−1]=[G][M2L−2]\left[\mathrm{ML}^{-2}\mathrm{T}^{-2}\right] = \left[\mathrm{h}\right]\left[\mathrm{T}^{-1}\right] = \left[\mathrm{G}\right]\left[\mathrm{M}^{2}\mathrm{L}^{-2}\right] [G]=[M−2L−1T−1h−1]\left[\mathrm{G}\right] = \left[\mathrm{M}^{-2}\mathrm{L}^{-1}\mathrm{T}^{-1}\mathrm{h}^{-1}\right]

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
2 April, Evening Shift
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Units and Dimensions Analysis

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