Physics · Current Electricity

JEE Main 2025 — 4 April, Morning Shift — Question 57

Current passing through a wire as function of time is given as I(t)=0.02t+0.01 AI(t)=0.02 t+0.01 \mathrm{~A}.

The charge that will flow through the wire from t=1 st=1 \mathrm{~s} to t=2 st=2 \mathrm{~s} is

  1. Option A:

    0.07 C

  2. Option B:

    0.06 C

  3. Option C:

    0.02 C

  4. Option D:

    0.04 C

    Correct

Answer: D

Step-by-step solution

i(t)=0.02t+0.01i(t)=0.02 t+0.01

q=∫idt=∫(0.02)tdt+0.01∫dt=0.022×(22−12)−0.01×1=0.04C\begin{aligned} q & =\int i d t \\ & =\int(0.02) t d t+0.01 \int d t \\ & =\frac{0.02}{2} \times\left(2^{2}-1^{2}\right)-0.01 \times 1 \\ & =0.04 \mathrm{C} \end{aligned}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Current Electricity
Topic
Current in Conductors, Drift Speed, Resistivity and Relaxation Time
Current passing through a wire as function of time is given as… | JEE Main 2025 PYQ with Solution · DhiX AI