Chemistry · Chemical Equilibrium

JEE Main 2026 — 23 January, Morning Shift — Question 65

Consider the general reaction given below at 400 K $\mathrm{xA}(\mathrm{g}) \rightleftharpoons \mathrm{yB}(\mathrm{g})$ The values of $\mathrm{K}_{\mathrm{p}}$ and $\mathrm{K}_{\mathrm{c}}$ are studied under the same condition of temperature but variation in x and y . (i) $\mathrm{K}_{\mathrm{p}}=85.87$ and $\mathrm{K}_{\mathrm{c}}=2.586$ appropriate units (ii) $\mathrm{K}_{\mathrm{p}}=0.862$ and $\mathrm{K}_{\mathrm{c}}=28.62$ appropriate units

The value of $x$ and $y$ in (i) and (ii) respectively are:

Option A:
(i) 3,1 ; (ii) 3,1
Option B:
(i) 4, 1 ; (ii) 4, 1
Option C:
(i) 1,3 ; (ii) 2,1
Option D:
(i) 1, 2 ; (ii) 2, 1
Correct

Answer: D

Step-by-step solution

For reaction (i) : $\mathrm{K}_{\mathrm{p}}>\mathrm{K}_{\mathrm{C}}$

\begin{aligned} & \Delta n_{g}>0 & y-x>0 . & 85.87=2.586(0.0821 \times 400)^{y-x} & \text { Solving } y-x \simeq 1 & \text { For reaction (ii) }: K_{p}<K_{C} & y-x<0 . \end{aligned}

Answer key and solution verified before publishing.

Practise Chemical Equilibrium

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2026
Paper: 23 January, Morning Shift
Subject: Chemistry
Chapter: Chemical Equilibrium
Topic: Analysis of Chemical Equilibrium, Equilibrium Constant and Reaction Quotient

For the following gas phase equilibrium reaction at constant temperature, NH 3( g) leftharpoons 1/2 N 2( g)+3/2 H 2( g) If the total…

Answer: D

Step-by-step solution

Practise Chemical Equilibrium

More Chemical Equilibrium questions from this paper