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Chemistry · Practical Inorganic chemistry (Qualitative Analysis)

JEE Main 2024 — 9 April, Shift 2 — Question 76

Consider the following test for a group-IV cation. M2++H2 S→ A\mathrm{M}^{2+}+\mathrm{H}_{2} \mathrm{~S} \rightarrow \mathrm{~A} (Black precipitate) + byproduct A+\mathrm{A}+ aqua regia

→B+NOCl+S+H2O\rightarrow \mathrm{B}+\mathrm{NOCl}+\mathrm{S}+\mathrm{H}_{2} \mathrm{O} B+KNO2+CH3COOH→C+\mathrm{B}+\mathrm{KNO}_{2}+\mathrm{CH}_{3} \mathrm{COOH} \rightarrow \mathrm{C}+ byproduct The spin only magnetic moment

value of the metal complex C is \qquad BM. (Nearest integer)

Answer: 0

Numerical answer — enter this value.

Step-by-step solution

Co2++H2 S→CoS↓\mathrm{Co}^{2+}+\mathrm{H}_{2} \mathrm{~S} \rightarrow \mathrm{CoS} \downarrow (Black) (A) CoS+\mathrm{CoS}+ Aqua-regia

→Co2+(aq)+NOCl+S+H2O\rightarrow \mathrm{Co}^{2+}(\mathrm{aq})+\mathrm{NOCl}+\mathrm{S}+\mathrm{H}_{2} \mathrm{O} (A) (B) Co2+(aq)+KNO2+CH3COOH\mathrm{Co}^{2+}(\mathrm{aq})+\mathrm{KNO}_{2}+\mathrm{CH}_{3} \mathrm{COOH}

K3[Co(NO2)6]+NO+S+H2O\mathrm{K}_{3}\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)_{6}\right]+\mathrm{NO}+\mathrm{S}+\mathrm{H}_{2} \mathrm{O}

In K3[Co(NO2)6],Co+3:3 d64 s0\mathrm{K}_{3}\left[\mathrm{Co}\left(\mathrm{NO}_{2}\right)_{6}\right], \mathrm{Co}^{+3}: 3 \mathrm{~d}^{6} 4 \mathrm{~s}^{0}

Co3+:d2sp3\mathrm{Co}^{3+}: \mathrm{d}^{2} \mathrm{sp}^{3} Hybridisation Number of unpaired e−=0\mathrm{e}^{-}=0 Magnetic moment =n(n+2)=0=\sqrt{\mathrm{n}(\mathrm{n}+2)}=0 B.M

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
9 April, Shift 2
Subject
Chemistry
Chapter
Practical Inorganic chemistry (Qualitative Analysis)
Topic
Identifical of Cations (Group 4 to 6 and Zero)