Chemistry · Alkyl and Aryl Halides

JEE Main 2025 — 28 January, Morning Shift — Question 48

Consider the following sequence of reactions :

figure

Chlorobenzene 11.25 mg of chlorobenzene will produce ___×10−1mg\times 10^{-1} \mathrm{mg} of product B.

 (Consider the reactions result in complete {\text { (Consider the reactions result in complete }} conversion.)

[Given molar mass of C,H,O,N\mathrm{C}, \mathrm{H}, \mathrm{O}, \mathrm{N} and Cl as 12,1 , 16,14 and 35.5 g mol−135.5 \mathrm{~g} \mathrm{~mol}^{-1} respectively]

Answer: 93

Numerical answer — enter this value.

Step-by-step solution

figure

11.25×10−3112.5=x×10−1×10−393\frac{11.25 \times 10^{-3}}{112.5}=\frac{\mathrm{x} \times 10^{-1} \times 10^{-3}}{93}

x×10−1=93×0.1\mathrm{x} \times 10^{-1}=93 \times 0.1

x=93mg\mathrm{x}=93 \mathrm{mg}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
Alkyl and Aryl Halides
Topic
Properties, Uses and Tests of Alkyl Halides
Consider the following sequence of reactions : Chlorobenzene 11.25 mg… | JEE Main 2025 PYQ with Solution · DhiX AI