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Chemistry · Practical Inorganic chemistry (Qualitative Analysis)

JEE Main 2026 — 23 January, Morning Shift — Question 54

Consider the following sequence of reactions. 4-Nitrotoluene Assuming that the reaction proceeds to completion, then 137 mg of 4-nitrotoluene will produce ____\_\_\_\_ mg of B . (Given molar mass in gmol−1H:1,C:12, N:14\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14, O :16, Br:80\mathrm{Br}: 80 )

Question figure
  1. Option A:

    301

  2. Option B:

    146

  3. Option C:

    228

    Correct
  4. Option D:

    208

Answer: C

Step-by-step solution

Mole =137×10−3137=0.001=\frac{137 \times 10^{-3}}{137}=0.001 mole Mole of product =0.001=0.001 mole Mass of product =0.001×228gm=0.001 \times 228 \mathrm{gm} =0.228gm=228mg=0.228 \mathrm{gm}=228 \mathrm{mg}

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
23 January, Morning Shift
Subject
Chemistry
Chapter
Practical Inorganic chemistry (Qualitative Analysis)
Topic
Identification of Anions
Consider the following sequence of reactions. 4-Nitrotoluene Assuming… | JEE Main 2026 PYQ with Solution · DhiX AI