Chemistry · Electrochemistry

JEE Main 2026 — 22 January, Evening Shift — Question 60

Consider the following reduction processes : Al3++3e−→Al(s),E∘=−1.66 V\mathrm{Al}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Al}(\mathrm{s}), \mathrm{E}^{\circ}=-1.66 \mathrm{~V} Fe3++e−→Fe2+,E0=+0.77 V\mathrm{Fe}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}^{2+}, \mathrm{E}^{0}=+0.77 \mathrm{~V} Co3++e−→Co2+,E∘=+1.81 V\mathrm{Co}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Co}^{2+}, \mathrm{E}^{\circ}=+1.81 \mathrm{~V} Cr3++3e−→Cr(s),E∘=−0.74 V\mathrm{Cr}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Cr}(\mathrm{s}), \mathrm{E}^{\circ}=-0.74 \mathrm{~V} The tendency to act as reducing agent decreases in the order :

  1. Option A:

    Al>Cr>Fe2+>Co2+\mathrm{Al}>\mathrm{Cr}>\mathrm{Fe}^{2+}>\mathrm{Co}^{2+}

    Correct
  2. Option B:

    Al>Fe2+>Cr>Co2+\mathrm{Al}>\mathrm{Fe}^{2+}>\mathrm{Cr}>\mathrm{Co}^{2+}

  3. Option C:

    Al>Cr>Co2+>Fe2+\mathrm{Al}>\mathrm{Cr}>\mathrm{Co}^{2+}>\mathrm{Fe}^{2+}

  4. Option D:

    Cr>Fe2+>Al>Co2+\mathrm{Cr}>\mathrm{Fe}^{2+}>\mathrm{Al}>\mathrm{Co}^{2+}

Answer: A

Step-by-step solution

Reducing power ∝1 Reduction potential \propto \frac{1}{\text { Reduction potential }}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Electrochemistry
Topic
Nernst Equation and Electrochemical Series
Consider the following reduction processes : Al 3+ +3 e - rightarrow… | JEE Main 2026 PYQ with Solution · DhiX AI