JEE Main 2024 — 4 April, Shift 1 — Question 79

$\text{Mn}{{\text{O}}_{2}}+\text{KOH}+{{\text{O}}_{2}}\to \text{ }\!\!~\!\!\text{ }{{\text{K}}_{2}}\text{Mn}{{\text{O}}_{4}}+{{\text{H}}_{2}}\text{O}$ (A) ${{\text{K}}_{2}}\text{Mn}{{\text{O}}_{4}}\overset{\text{ }\!\!~\!\!\text{ Neutral/acidic }\!\!~\!\!\text{ solution }\!\!~\!\!\text{ }\!\!~\!\!\text{ }}{\mathop{\to }}\,\text{KMn}{{\text{O}}_{4}}+\text{Mn}{{\text{O}}_{2}}$ $\text{M}{{\text{n}}^{+4}}:-\left[ \text{Ar} \right]3\text{ }\!\!~\!\!\text{ }{{\text{d}}^{3}}$ $\text{n}=3,\mu =\sqrt{3\left( 3+2 \right)}=3.87$ B.M.

Nearest integer is (4)